Sandomhet

PHYS 7B: Basic Physics II

Notes for PHYS 7B: Basic Physics II, covering topics such as gravitation, oscillations, and wave motion.

Tue, Mar 31, 2026 11 min read

PHYS 7B: Basic Physics II

Gravitation

Universal Law of Gravitation:

FG=Gm1m2r2F_G = G \frac{m_1 m_2}{r^2}

where G≈6.67×10−11 N⋅m2/kg2G \approx 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 is the gravitational constant.

Gravitational Field:

g=FGm=GMr2g = \frac{F_G}{m} = G \frac{M}{r^2}

Satellite Motion

For a satellite in circular orbit around a planet: FG=mv2r=GMmr2F_G = \frac{mv^2}{r} = G \frac{Mm}{r^2} which leads to the orbital velocity: v=GMrv = \sqrt{\frac{GM}{r}}

aR=v2r=GMr2=ga_R = \frac{v^2}{r} = \frac{GM}{r^2} = g is the centripetal acceleration, which is equal to the gravitational acceleration at that radius.

The period of the satellite is: T=2πrv=2πr3GMT = \frac{2\pi r}{v} = 2\pi \sqrt{\frac{r^3}{GM}} This is known as Kepler's Third Law.

Escape Velocity

The escape velocity from a planet is the minimum velocity needed for an object to escape the gravitational pull of the planet without further propulsion: vesc=2GMRv_{esc} = \sqrt{\frac{2GM}{R}} where RR is the radius of the planet.

Gravitational Potential Energy

The work against gravity to move a mass mm from a distance r1r_1 to r2r_2 is given by: W=∫r1r2FG dr=∫r1r2GMmr2 dr=GMm(1r2−1r1)W = \int_{r_1}^{r_2} F_G \, dr = \int_{r_1}^{r_2} G \frac{Mm}{r^2} \, dr = G Mm \left( \frac{1}{r_2} - \frac{1}{r_1} \right) The gravitational potential energy at a distance rr from a mass MM is, where U(∞)=0U(\infty) = 0: U(r)=−GMmrU(r) = -G \frac{Mm}{r}

The negative sign indicates that the potential energy is lower (more negative) when the masses are closer together, reflecting the attractive nature of gravity. The potential energy approaches zero as rr approaches infinity, which means that it takes an infinite amount of energy to separate the masses completely.

Geostationary Orbits

A geostationary orbit is a circular orbit around the Earth where the satellite's orbital period matches the Earth's rotation period (24 hours). The radius of a geostationary orbit can be found using Kepler's Third Law: T2=4π2R3GMT^2 = \frac{4\pi^2 R^3}{GM} R3=GMT24π2R^3 = \frac{GMT^2}{4\pi^2}

Oscillations

Simple Harmonic Oscillator

Hooke's Law: Fs=−kxF_s = -kx where kk is the spring constant and xx is the displacement from equilibrium.

F=ma−kx=md2xdt2d2xdt2+kmx=0ω=km\begin{aligned} F &= ma \\ -kx &= m \frac{d^2x}{dt^2} \\ \frac{d^2x}{dt^2} + \frac{k}{m} x &= 0 \\ \omega &= \sqrt{\frac{k}{m}} \\ \end{aligned}

The general solution to the equation of motion is: x(t)=Acos⁡(ωt+ϕ)x(t) = A \cos(\omega t + \phi) where AA is the amplitude, ω\omega is the angular frequency, and ϕ\phi is the phase constant determined by initial conditions.

  • Period: T=2πω=2πmk T = \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{m}{k}}.
  • The total energy of the system is conserved and given by: E=12mv2+12kx2=12kA2E = \frac{1}{2}mv^2 + \frac{1}{2}kx^2 = \frac{1}{2}kA^2 Thus, x2+(vω)2=A2x^2 + \left( \frac{v}{\omega} \right)^2 = A^2.

ϕ=arctan⁡(−v0ωx0)\phi = \arctan\left( -\frac{v_0}{\omega x_0} \right).

Simple Pendulum

For small angles (θ≈sin⁡θ\theta \approx \sin \theta):

Fθ=maθ−mgsin⁡θ=mLα−mgsin⁡θ=mLd2θdt2d2θdt2+gLθ=0ω=gL\begin{aligned} F_\theta &= ma_\theta \\ -mg \sin \theta &= mL\alpha \\ -mg \sin \theta &= mL \frac{d^2\theta}{dt^2} \\ \frac{d^2\theta}{dt^2} + \frac{g}{L} \theta &= 0 \\ \omega &= \sqrt{\frac{g}{L}} \\ \end{aligned}

where LL is the length of the pendulum and gg is the acceleration due to gravity.

The period is: T=2πLgT = 2\pi \sqrt{\frac{L}{g}}

Physical Pendulum

For a physical pendulum, the moment of inertia II and the distance dd from the pivot to the center of mass are used:

τ=Iα−mgdsin⁡θ=Id2θdt2d2θdt2+mgdIθ=0ω=mgdI\begin{aligned} \tau &= I \alpha \\ -mgd \sin \theta &= I \frac{d^2\theta}{dt^2} \\ \frac{d^2\theta}{dt^2} + \frac{mgd}{I} \theta &= 0 \\ \omega &= \sqrt{\frac{mgd}{I}} \\ \end{aligned}

The period is: T=2πImgdT = 2\pi \sqrt{\frac{I}{mgd}}

Wave Motion

Mechanical waves: disturbances that propagate through a medium, transferring energy without transferring matter.

Longitudinal waves: particles of the medium oscillate parallel to the direction of wave propagation (e.g., sound waves).
Transverse waves: particles of the medium oscillate perpendicular to the direction of wave propagation (e.g., waves on a string).

Sinusoidal Wave

  • Crest: the highest point of the wave.
  • Trough: the lowest point of the wave.
  • Amplitude (AA): the maximum displacement of the wave from its equilibrium position. (the height of the crest or trough)
  • Wavelength (λ\lambda): the distance between two consecutive crests or troughs.
  • Frequency (ff): the number of oscillations per unit time.
  • Period (TT): the time it takes for one complete oscillation, T=1fT = \frac{1}{f}.
  • Angular frequency (ω\omega): the temporal frequency of the wave, ω=2πf=2πT\omega = 2\pi f = \frac{2\pi}{T}.
  • Wave speed (vv): the speed at which the wave propagates through the medium, v=λf=λT=ωkv = \lambda f = \frac{\lambda}{T} = \frac{\omega}{k}.
  • Wave number (kk): the spatial frequency, k=2πλ=ωvk = \frac{2\pi}{\lambda} = \frac{\omega}{v}.

Snapshot y(x)=Asin⁡(kx+ϕ)y(x) = A \sin(kx + \phi)

Traveling wave y(x,t)=Asin⁡(kx−ωt+ϕ)y(x, t) = A \sin(kx - \omega t + \phi)

Classical Wave Equation

∂2y∂x2=1v2∂2y∂t2\frac{\partial^2 y}{\partial x^2} = \frac{1}{v^2} \frac{\partial^2 y}{\partial t^2} yy is the wave function, xx is the spatial coordinate, tt is time, and vv is the wave speed. The left-hand side represents the spatial curvature of the wave, while the right-hand side represents the temporal curvature.

Transverse Waves on a String

The wave speed on a string is given by: v=Fμv = \sqrt{\frac{F}{\mu}} where FF is the tension force in the string and μ=dmdx\mu = \frac{dm}{dx} is the linear mass density. v=λf=λTv = \lambda f = \frac{\lambda}{T}

Coexisting Waves

Principle of superposition: when two or more waves overlap, the resulting wave is the sum of the individual waves.

  • Constructive interference: when waves are in phase, their amplitudes add up, resulting in a larger amplitude.
  • Destructive interference: when waves are out of phase, their amplitudes subtract, resulting in a smaller amplitude or complete cancellation.

Wave Boundary

  • Fixed boundary: the wave is reflected and inverted (phase change of π\pi).
  • Free boundary: the wave is reflected without inversion (no phase change).

Standing Waves

  • Incident wave: yi(x,t)=Acos⁡(kx−ωt)y_i(x, t) = A \cos(kx - \omega t)
  • Reflected wave: yr(x,t)=−Acos⁡(kx+ωt)y_r(x, t) = -A \cos(kx + \omega t)

Resulting wave: y(x,t)=2Asin⁡(kx)sin⁡(ωt)y(x, t) = 2A \sin(kx) \sin(\omega t)

2Asin⁡(kx)2A \sin(kx) is the amplitude of the standing wave, which varies with position xx. The time-dependent part sin⁡(ωt)\sin(\omega t) oscillates between -1 and 1, but the spatial part determines where the nodes and antinodes are located.

  • Nodes: points where the amplitude is always zero (destructive interference).
  • Antinodes: points where the amplitude is maximum (constructive interference). The distance between adjacent nodes or antinodes is λ2\frac{\lambda}{2}, and the distance between a node and the nearest antinode is λ4\frac{\lambda}{4}.

Vibrating String

Fundamental Mode: n=1n=1, λ1=2L\lambda_1 = 2L, f1=v2Lf_1 = \frac{v}{2L}

For a string fixed at both ends, the allowed wavelengths are: λn=2Ln\lambda_n = \frac{2L}{n} where LL is the length of the string and nn is a positive integer (the mode number). The corresponding frequencies are: fn=vλn=nv2Lf_n = \frac{v}{\lambda_n} = \frac{n v}{2L} where vv is the wave speed on the string. The fundamental frequency (first harmonic) corresponds to n=1n=1, the second harmonic corresponds to n=2n=2, and so on. Each mode of vibration produces a standing wave pattern with n−1n-1 nodes between the fixed ends.

yn(x,t)=2Ansin⁡(knx)sin⁡(ωnt)kn=nπLωn=2πfn=nπvL\begin{aligned} y_n(x, t) &= 2A_n \sin\left( k_n x \right) \sin(\omega_n t) \\ k_n &= \frac{n \pi}{L} \\ \omega_n &= 2\pi f_n = \frac{n \pi v}{L} \end{aligned}

Sound Waves

Sound waves are longitudinal waves that propagate through a medium by compressing and rarefying the particles of the medium.

y(x,t)=Acos⁡(kx−ωt+ϕ)p(x,t)=pmaxsin⁡(kx−ωt+ϕ)y(x, t) = A \cos(kx - \omega t + \phi) \\ p(x, t) = p_{max} \sin(kx - \omega t + \phi)

v=restoring forceinertiav = \frac{\text{restoring force}}{\text{inertia}}

In air, v≈340 m/sv \approx 340 \, \text{m/s}, in water v≈1500 m/sv \approx 1500 \, \text{m/s}, and in steel v≈5000 m/sv \approx 5000 \, \text{m/s}.

Standing Sound Waves in a Pipe

  • Open at both ends: λn=2Ln\lambda_n = \frac{2L}{n}, fn=nv2Lf_n = \frac{n v}{2L}, n=1,2,3,…n=1, 2, 3, \ldots
  • Closed at one end: λn=4Ln\lambda_n = \frac{4L}{n}, fn=nv4Lf_n = \frac{n v}{4L}, n=1,3,5,…n=1, 3, 5, \ldots (only odd harmonics)

Superposition: The difference in path length traveled by two waves determines the type of interference:

  • Constructive interference: ΔL=mλ\Delta L = m \lambda where mm is an integer.
  • Destructive interference: ΔL=(m+12)λ\Delta L = (m + \frac{1}{2}) \lambda where mm is an integer.

Electrostatics

  • Conductors: materials that allow electrons to flow freely (e.g., metals).
  • Insulators: materials that do not allow electrons to flow freely (e.g., rubber, glass).
  • Semiconductors: materials that have electrical conductivity between that of conductors and insulators (e.g., silicon).

Coulomb's Law

Coulomb's Law: The electrostatic force between two point charges:

Fe⃗=kq1q2r2r^\vec{F_e} = k \frac{q_1 q_2}{r^2} \hat{r}

where kk is the electrostatic constant.

k=14πϵ0≈8.99×109 N⋅m2/C2ϵ0≈8.854×10−12 C2/N⋅m2e≈1.602×10−19 Ck = \frac{1}{4\pi\epsilon_0} \approx 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \\ \epsilon_0 \approx 8.854 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \\ e \approx 1.602 \times 10^{-19} \, \text{C}
  • attractive if the charges have opposite signs
  • repulsive if they have the same sign.

Electric Field

The electric field E⃗\vec{E} at a point in space is defined as the force F⃗\vec{F} experienced by a positive test charge qq placed at that point, divided by the magnitude of the test charge:

E⃗=F⃗q\vec{E} = \frac{\vec{F}}{q}

The electric field due to a point charge QQ at a distance rr is given by:

E⃗=kQr2r^\vec{E} = k \frac{Q}{r^2} \hat{r}

Continuous charge distribution

E⃗=k∫dqr2r^\vec{E} = k \int \frac{dq}{r^2} \hat{r}
  1. Line charge distribution: dq=λdxdq = \lambda dx, E⃗=2kλrr^\vec{E} = \frac{2k\lambda}{r} \hat{r} where rr is the distance from the line charge to the point.
    • E⃗=∫kdqr2r^=kλ∫dxr2r^=2kλ∫0∞dxx2+r2r^=2kλ[xr2x2+r2]0∞=2kλ1rr^\vec{E} = \int \frac{k dq}{r^2} \hat{r} = k \lambda \int \frac{dx}{r^2} \hat{r} = 2k\lambda \int_0^\infty \frac{dx}{x^2 + r^2} \hat{r} = 2k\lambda \left[ \frac{x}{r^2 \sqrt{x^2 + r^2}} \right]_0^\infty = 2k\lambda \frac{1}{r} \hat{r}.
  2. Ring charge distribution: dq=λdldq = \lambda dl, E⃗=kxQ(x2+R2)3/2x^\vec{E} = \frac{kxQ}{(x^2 + R^2)^{3/2}} \hat{x} where RR is the radius of the ring and xx is the distance from the center of the ring along the axis perpendicular to the plane of the ring.
  3. Disk charge distribution: dq=σdA=σ2πrdrdq = \sigma dA = \sigma 2\pi r dr, E⃗=σ2ϵ0(1−xx2+R2)x^\vec{E} = \frac{\sigma}{2\epsilon_0} \left(1 - \frac{x}{\sqrt{x^2 + R^2}} \right) \hat{x} where RR is the radius of the disk.
    • E⃗=∫kxdq(x2+r2)3/2=kxσ2π∫0Rr(x2+r2)3/2dr=2πkσ(1−xx2+R2)x^=σ2ϵ0(1−xx2+R2)x^\vec{E} = \int \frac{kx dq}{(x^2 + r^2)^{3/2}} = kx \sigma 2\pi \int_0^R \frac{r}{(x^2 + r^2)^{3/2}} dr = 2\pi k \sigma \left(1 - \frac{x}{\sqrt{x^2 + R^2}} \right) \hat{x} = \frac{\sigma}{2\epsilon_0} \left(1 - \frac{x}{\sqrt{x^2 + R^2}} \right) \hat{x}
    • For R≫xR \gg x, E⃗≈σ2ϵ0x^\vec{E} \approx \frac{\sigma}{2\epsilon_0} \hat{x} (infinite plane approximation).
  4. Surface charge distribution: dq=σdAdq = \sigma dA, E⃗=σ2ϵ0n^\vec{E} = \frac{\sigma}{2\epsilon_0} \hat{n}
    • E⃗=∫kdqr2r^=kσ∫dAr2n^=kσ4πn^=σ2ϵ0n^\vec{E} = \int \frac{k dq}{r^2} \hat{r} = k \sigma \int \frac{dA}{r^2} \hat{n} = k \sigma 4\pi \hat{n} = \frac{\sigma}{2\epsilon_0} \hat{n} where n^\hat{n} is the unit normal vector to the surface.
  5. Volume charge distribution: dq=ρdVdq = \rho dV, E⃗=ρ3ϵ0r^\vec{E} = \frac{\rho}{3\epsilon_0} \hat{r}

Field Lines

  • The direction of the electric field at any point is tangent to the field line at that point.
  • The magnitude of the electric field is proportional to the density of the field lines: the closer the field lines are to each other, the stronger the electric field at that point.
  • Field lines begin on positive charges and end on negative charges.
  • Field lines never cross each other.

Electric Dipole

An electric dipole consists of two equal and opposite charges separated by a distance dd. The dipole moment p⃗\vec{p} is defined as:

p⃗=qd⃗\vec{p} = q \vec{d}

Direction: from the negative charge to the positive charge.

Torque τ⃗=p⃗×E⃗\vec{\tau} = \vec{p} \times \vec{E}

Potential energy U=−p⃗⋅E⃗U = -\vec{p} \cdot \vec{E}

Electric Flux

The electric flux ΦE\Phi_E through a surface is defined as the total electric field passing through that surface: ΦE=E⊥A=EAcos⁡ϕ=E⃗⋅A⃗\Phi_E = E_\perp A = EA \cos \phi = \vec{E} \cdot \vec{A} ΦE=∫E⃗⋅dA⃗\Phi_E = \int \vec{E} \cdot d\vec{A} where E⊥E_\perp is the component of the electric field perpendicular to the surface, AA is the area of the surface, and ϕ\phi is the angle between the electric field and the normal to the surface.

Gauss's Law

ΦE=∮E⃗⋅dA⃗=Qencϵ0\Phi_E = \oint \vec{E} \cdot d\vec{A} = \frac{Q_{enc}}{\epsilon_0} where QencQ_{enc} is the total charge enclosed within the Gaussian surface.

For a point charge QQ at the center of a spherical Gaussian surface of radius rr: ΦE=E⋅4πr2=Qϵ0  ⟹  E=kQr2\Phi_E = E \cdot 4\pi r^2 = \frac{Q}{\epsilon_0} \implies E = k \frac{Q}{r^2}

For a charged insulating sphere with total charge QQ and radius RR:

  • For r<Rr < R: Qenc=Qr3R3Q_{enc} = \frac{Qr^3}{R^3}, E=kQrR3=14πϵ0QrR3E = k \frac{Qr}{R^3} = \frac{1}{4\pi\epsilon_0} \frac{Qr}{R^3}
  • For r≥Rr \geq R: Qenc=QQ_{enc} = Q, E=kQr2=14πϵ0Qr2E = k \frac{Q}{r^2} = \frac{1}{4\pi\epsilon_0} \frac{Q}{r^2}

For a charged conducting sphere with total charge QQ and radius RR:

  • For r<Rr < R: Qenc=0Q_{enc} = 0, E=0E = 0
  • For r≥Rr \geq R: Qenc=QQ_{enc} = Q, E=kQr2=14πϵ0Qr2E = k \frac{Q}{r^2} = \frac{1}{4\pi\epsilon_0} \frac{Q}{r^2}

Electric Potential Energy

We,a→b=∫abF⃗e⋅dr⃗=k∫abqq0r2dr=kqq0(1ra−1rb)W_{e, a\to b} = \int_a^b \vec{F}_{e} \cdot d\vec{r} = k \int_a^b \frac{q q_0}{r^2} dr = k q q_0 \left( \frac{1}{r_a} - \frac{1}{r_b} \right) ΔU=Ub−Ua=−We,a→b=kqq0(1rb−1ra)\Delta U = U_b - U_a = -W_{e, a\to b} = k q q_0 \left( \frac{1}{r_b} - \frac{1}{r_a} \right) U=kq1q2rU = k \frac{q_1 q_2}{r}

Electric Potential

V=Uq=kQr=EdV = \frac{U}{q} = k \frac{Q}{r} = Ed

where 1 V (volt)=1 J/C1 \, \text{V (volt)} = 1 \, \text{J/C}.

Voltage: Vba=Vb−Va=ΔUq=−∫abE⃗⋅dr⃗V_{ba} = V_b - V_a = \frac{\Delta U}{q} = -\int_a^b \vec{E} \cdot d\vec{r}

Multiple point charge sources: V=k∑qiriV = k \sum \frac{q_i}{r_i}.
Continuous charge distribution: V=k∫dqrV = k \int \frac{dq}{r}.

For a charged conducting sphere

  • outside the sphere, the potential is the same as if all the charge were concentrated at the center
  • inside the sphere, the potential is constant and equal to the potential at the surface.

For a charged insulating sphere

  • outside the sphere, the potential is the same as if all the charge were concentrated at the center
  • inside the sphere, the potential is given by V=kQ2R3(3R2−r2)V = k \frac{Q}{2R^3} (3R^2 - r^2).

Electric field lines point from higher potential to lower potential.

Capacitance

Capacitor: two conductors separated by an insulating material (air).
Capacitance is the ability to store electrical charge.

C=QV=QEd=ϵ0AdC = \frac{Q}{V} = \frac{Q}{E d} = \frac{\epsilon_0 A}{d}

units: 1 F (farad)=1 C/V1 \, \text{F (farad)} = 1 \, \text{C/V}.

Spherical capacitor: C=4πϵ0rarbrb−raC = 4\pi \epsilon_0 \frac{r_a r_b}{r_b - r_a} where rar_a and rbr_b are the radii of the inner and outer spheres, respectively.

  • Capacitors in series: 1Ceq=∑1Ci\frac{1}{C_{eq}} = \sum \frac{1}{C_i} (same charge)
  • Capacitors in parallel: Ceq=∑CiC_{eq} = \sum C_i (same voltage)

Energy stored in a capacitor:

U=∫0QV dQ=12CV2=12QV=12Q2CU = \int_0^Q V \, dQ = \frac{1}{2} CV^2 = \frac{1}{2} QV = \frac{1}{2} \frac{Q^2}{C}

Energy density in an electric field:

u=UAd=12ϵ0E2u = \frac{U}{Ad} = \frac{1}{2} \epsilon_0 E^2

Dielectrics

When the capacitor is filled with a dielectric material, the capacitance increases by a factor of the dielectric constant κ\kappa: C′=κCC' = \kappa C E′=EκE' = \frac{E}{\kappa} V′=VκV' = \frac{V}{\kappa}

Electric Circuits

Electric Current

Electric current II is the rate of flow of electric charge:

I=dQdt=nqAvdI = \frac{dQ}{dt} = nqAv_d

where nn is the number of charge carriers per unit volume, qq is the charge of each carrier, AA is the cross-sectional area of the conductor, and vdv_d is the drift velocity of the charge carriers.
units: 1 A (ampere)=1 C/s1 \, \text{A (ampere)} = 1 \,\text{C/s}.

  • Conventional current: positive charges would move, which is opposite to the actual flow of electrons.
  • Real current: the actual flow of electrons, from the negative terminal to the positive terminal.

Resistance

Ohm's Law:

R=VI=ρLAR = \frac{V}{I} = \frac{\rho L}{A}

where ρ\rho is the resistivity of the material, LL is the length of the conductor, and AA is the cross-sectional area.
units: 1 Ω(ohm)=1 V/A1 \, \Omega (\text{ohm}) = 1 \, \text{V/A}.

Resistivity of metals:

ρ=EJ\rho = \frac{E}{J}

where EE is the electric field and JJ is the current density.

  • Resistors in series: Req=∑RiR_{eq} = \sum R_i (same current)
  • Resistors in parallel: 1Req=∑1Ri\frac{1}{R_{eq}} = \sum \frac{1}{R_i} (same voltage)

Battery

Battery: a device that converts chemical energy into electrical energy, providing a potential difference (voltage) to drive current through a circuit.

Electromotive force (emf) E\mathcal{E}: the maximum potential difference provided by the battery when no current is flowing.
Internal resistance rr: the resistance within the battery that causes a voltage drop when current flows.
Terminal voltage VV: the actual voltage across the battery terminals when current is flowing, given by

V=E−IrV = \mathcal{E} - Ir

Power

Power delivered by the battery:

P=IV=I(E−Ir)=IE−I2rP = IV = I(\mathcal{E} - Ir) = I\mathcal{E} - I^2 r

Power delivered to the resistor:

PR=IV=I2R=V2RP_R = IV = I^2 R = \frac{V^2}{R}

The first term IEI\mathcal{E} represents the power supplied by the battery, while the second term I2rI^2 r represents the power lost due to the internal resistance of the battery. The efficiency of the battery can be calculated as Efficiency=PusefulPtotal=IE−I2rIE=1−IrE\text{Efficiency} = \frac{P_{\text{useful}}}{P_{\text{total}}} = \frac{I\mathcal{E} - I^2 r}{I\mathcal{E}} = 1 - \frac{Ir}{\mathcal{E}}

Kirchhoff's Laws

  • Kirchhoff's Current Law (KCL): The total current entering a junction equals the total current leaving the junction.
  • Kirchhoff's Voltage Law (KVL): The sum of the potential differences around any closed loop in a circuit must equal zero.

RC (Resistor-Capacitor) Circuits

Equations:

∑V=0⇒E−iR−qC=0i=dqdt⇒dqdt=ER−qRCdqdt=q−EC−RC∫0Qdqq−EC=−∫0tdtRCln⁡∣q−EC−EC∣=−tRC\begin{aligned} \sum V = 0 &\Rightarrow \mathcal{E} - iR - \frac{q}{C} = 0 \\ i = \frac{dq}{dt} &\Rightarrow \frac{dq}{dt} = \frac{\mathcal{E}}{R} - \frac{q}{RC} \\ \frac{dq}{dt} &= \frac{q - \mathcal{E}C}{-RC} \\ \int_0^Q \frac{dq}{q - \mathcal{E}C} &= -\int_0^t \frac{dt}{RC} \\ \ln \left| \frac{q - \mathcal{E}C}{-\mathcal{E}C} \right| &= -\frac{t}{RC} \\ \end{aligned}

When a capacitor is charging through a resistor:

Q(t)=CE(1−e−tRC)V(t)=E(1−e−tRC)I(t)=ERe−tRC\begin{aligned} Q(t) &= C \mathcal{E} \left(1 - e^{-\frac{t}{RC}} \right) \\ V(t) &= \mathcal{E} \left(1 - e^{-\frac{t}{RC}} \right) \\ I(t) &= \frac{\mathcal{E}}{R} e^{-\frac{t}{RC}} \\ \end{aligned}

Charge increases in a characteristic time scale where time constant is τ=RC\tau = RC.

When a capacitor is discharging through a resistor:

Q(t)=Q0e−tRCV(t)=V0e−tRCI(t)=−V0Re−tRC\begin{aligned} Q(t) &= Q_0 e^{-\frac{t}{RC}} \\ V(t) &= V_0 e^{-\frac{t}{RC}} \\ I(t) &= -\frac{V_0}{R} e^{-\frac{t}{RC}} \\ \end{aligned}
Search

Loading search…